Samuel drops a 2kg ball from some height above the surface of a table. The ball starts from rest and loses 36 Joules of gravitational potential energy before reaching the table’s surface. What is the speed of the ball just before it hits the table?

If needed, g=10ms2

asked by juanpro

11 years ago

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1 answer

just set

1/2 mv^2 = 36

and solve for v

answered by Steve

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Question

Samuel drops a 2kg ball from some height above the surface of a table. The ball starts from rest and loses 36 Joules of gravitational potential energy before reaching the table’s surface. What is the speed of the ball just before it hits the table?

If needed, g=10ms2

1 answer

just set

1/2 mv^2 = 36

and solve for v

If needed, g=10ms2

Steve · Answer

just set 1/2 mv^2 = 36 and solve for v