Asked by Frustrated
simplify: (sinx/cosx)-1/(cosx/sinx)-1
Answers
Answered by
Reiny
I too am slightly frustrated, since I can't tell which order of operation to follow with your placement of brackets
is it sinx/cosx - [1/(sinx/cosx)] - 1 ??
if so, you have
tanx - 1/cotx - 1
= tanx - tanx - 1
= -1
is it sinx/cosx - [1/(sinx/cosx)] - 1 ??
if so, you have
tanx - 1/cotx - 1
= tanx - tanx - 1
= -1
Answered by
ATTN REINY
(sinx/cosx-1)/ (cosx/sinx-1)
Answered by
Damon
(tan x -1) / (1/tan x - 1)
(tan^2 x - tan x) / (1 - tan x)
tan x (tan x - 1)/(1 - tan x)
-tan x
(tan^2 x - tan x) / (1 - tan x)
tan x (tan x - 1)/(1 - tan x)
-tan x
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