Asked by cookie monster

a 2.0 kg crate is incline at 60degrees and is held in equilibrium by a horizontal force..
what is the magnitude of this horizontal force? (disregard friction)
Answered by drwls
The inclines applies a force M g cos 60 = M g/2 to the crate, in a direction normal to the incline surface. The horizontal component of that force equals the force that keeps it in equilibrium.

I will leave you to compute that
Answered by cookie monster
is the horizontal force the same as the normal force?
Answered by drwls
No. The normal force is perpendicular to the incline surface
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