Asked by Anonymous
What mass of NO2 is formed by the complete reaction of 2 mol O3 with excess NO in the reaction?
O3 + NO --> O2 + NO2
I know the molar mass of O3 is 48 g/mol and NO2 46 g/mol
a) 23.0 g
b) 46.0 g
c) 92.0 g
d) 96.0 g
O3 + NO --> O2 + NO2
I know the molar mass of O3 is 48 g/mol and NO2 46 g/mol
a) 23.0 g
b) 46.0 g
c) 92.0 g
d) 96.0 g
Answers
Answered by
DrBob222
Use the coefficients to convert mols of what you have to mols of what you want.
2 mols O3 x (1 mol NO2/1 mol O3) = 2 x 1/1 = 2 mols NO2.
Now convert mols NO2 to grams. Grams = mols NO2 x molar mass NO2 = ?
2 mols O3 x (1 mol NO2/1 mol O3) = 2 x 1/1 = 2 mols NO2.
Now convert mols NO2 to grams. Grams = mols NO2 x molar mass NO2 = ?
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