Asked by MsHemmoPenguin
What mass of an NO2 is formed when and NO reacts with 384 g of O2?
Answers
Answered by
bobpursley
2NO+O2>>2NO2
the moles of NO2 will be twice the moles of O2
MolesNO2=384/32
massNO2=molesNO2*(14+32)
All this assumes NO is in excess in the reaction
the moles of NO2 will be twice the moles of O2
MolesNO2=384/32
massNO2=molesNO2*(14+32)
All this assumes NO is in excess in the reaction
Answered by
Zain
How many grams of NO are required to react with this amount of O2
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