4*12+10 = 58 grams/mol
14.17/58 = .244 mol
2C4H10 + 13 O2 ---> 10H2O + 8 CO2
mols CO2 produced = .244(8/2)=.977 mol
2*12+16 = 40 grams/mol
40 g/mol * .977 mol = 39.1 grams
what mass of CO2 can be formed when 14.17g of C4H10 are burned in excess oxygen
I do not even know where to start
1 answer