Asked by shay
four diesel ships left a port at noon;january2,1953.the first ship returns to this port every 4 weeks, the second every 8, the third every 12,and the fourth every 16.when did all four ships meet again in the port?
Answers
Answered by
drwls
The number of weeks later would be the lowest common multiple of 4,8,12 and 16.
That number would have to have as prime factors at least four 2's, and one 3. That means the ships return together
2^4 x 3 = ? weeks later.
Assume it is not a leap year
That number would have to have as prime factors at least four 2's, and one 3. That means the ships return together
2^4 x 3 = ? weeks later.
Assume it is not a leap year
Answered by
shae
so the answer is 48 but how many days was in the year; with leep years
Answered by
drwls
What is 48 weeks after Janaury 2?
1953 was not a leap year.
You do the counting. Don't use a 2008 calendar.
1953 was not a leap year.
You do the counting. Don't use a 2008 calendar.
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