Asked by Hannah
a ball is thrown upwards from a tower standing 300 feet tall. the initial velocity of the ball is 32 feet/second. the negative acceleration of the ball due to gravity is -16 in terms of feet per second squared. What is the velocity of the ball after 1 second?
Answers
Answered by
Reiny
h = -16t^2 + 32t + 300 , from your data
v = dh/dt
= -32t + 32
so when t = 1
v = -32 + 32 = 0
v = dh/dt
= -32t + 32
so when t = 1
v = -32 + 32 = 0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.