Asked by Aveena

A ball is allowed to fall from the top of the tower 200m high. At the same instant another ball is thrown vertically upwards from the bottom of the tower with velocity of 40m/s. When and where the two balls meet?

Answers

Answered by bobpursley
ball1:
h=200-4.8t^2
ball2:
h=40*t-4.8t^2

subtract the equations.
0=200-40t
t= 5 seconds
where? h=200-4.8*5^2


Answered by Ish Anand
Time=5 seconds & Height=77.5 meters.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions