Question

A body is allowed to fall from rest through a vertical height of 8.45 m.
Gravitational acceleration is 9.8 mis2. Calculate the velocity of the body at the end of the fall.

Answer 1

V^2 = Vo^2 + 2g*h.
V^2 = 0 + 19.6*8.45 = 165.62
V = 12.87 m/s.