V = Vo + g*t = 16 - 9.8*1.5 = 1.3 m/s.
Your answers are correct.
After the ball leaves the hand of the thrower, what is the value of acceleration acting on the ball as it is rising upwards?
9.8x1.5 = 14.7. 16-14.7=1.3 m/s after 1.5s.
The value of acceleration acting on the ball is -9.8 m/s, due to gravity.
Is this correct?
Your answers are correct.
To calculate the velocity, you need to break down the problem into two separate scenarios: when the ball is moving upward and when it is moving downward.
First, let's calculate the time it takes for the ball to reach its peak height. The equation to determine the time of flight is given by:
time = (final velocity - initial velocity) / acceleration
Here, the initial velocity is 16 m/s, the final velocity will be 0 m/s (as the ball reaches its peak height, it momentarily stops), and the acceleration is -9.8 m/s^2 (negative because it acts in the opposite direction of the initial velocity). Plugging in these values:
time = (0 - 16) / -9.8
Solving for time, we find:
time = 1.63 seconds
Now that we have the time it takes for the ball to reach its peak height, we can determine the velocity after 1.5 seconds.
For the first part of the motion (upward), we know the initial velocity is 16 m/s and the acceleration is -9.8 m/s^2. Using the equation:
velocity = initial velocity + (acceleration * time)
Plugging in the values:
velocity = 16 + (-9.8 * 1.5)
Solving for velocity, we get:
velocity = 16 + (-14.7) = 1.3 m/s
So, the velocity of the ball 1.5 seconds later is 1.3 m/s.
Regarding the value of acceleration acting on the ball as it is rising upward, it is indeed -9.8 m/s^2. The negative sign indicates that the velocity is decreasing as the ball moves against the direction of gravity.