Asked by Anonymous ~ 2nd Year
A mother is x years old, her son is y years old and the sum of theirs ages together is 58 years. Five years ago, the mother was five times as old as the son. Write two equations in x and y and solve them to find the age of their mother and age of the son.
I have found out the answer, but the problem is that I do not know the METHOD of finding the answer.
Please reply asap if you are able. Thank You.
Answers:
Mother = 45
Son = 13
I have found out the answer, but the problem is that I do not know the METHOD of finding the answer.
Please reply asap if you are able. Thank You.
Answers:
Mother = 45
Son = 13
Answers
Answered by
Steve
the method is just to write the words as math:
<u>mother is x years old, her son is y years old and the sum of theirs ages together is 58</u>
x+y = 58
<u>Five years ago, the mother was five times as old as the son</u>
(x-5) = 5(y-5)
Now it's easy!
x+y=58
x-5y = -20
subtract and you get
6y = 78
y = 13
so, x=58-y = 45
5 years ago they were 40 and 8; 40=5*8
<u>mother is x years old, her son is y years old and the sum of theirs ages together is 58</u>
x+y = 58
<u>Five years ago, the mother was five times as old as the son</u>
(x-5) = 5(y-5)
Now it's easy!
x+y=58
x-5y = -20
subtract and you get
6y = 78
y = 13
so, x=58-y = 45
5 years ago they were 40 and 8; 40=5*8
Answered by
Graham
How do you get x-5y = -20
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