Asked by triz
five years ago, a mother was twice as old as her son. In 6 years time, the sum of their ages will be 82. Fiind their present age.
Answers
Answered by
C
Let x be mother and y be son
Equation 1 : x - 5 = 2*(y - 5)
Equation 2: x + 6 + y + 6 = 82
x - 5 = 2y -10 (1)
x + y + 12 = 82 (2)
x -2y = -5
x + y = 70 [Eliminate x]
-3y = -75
y = 25 [Son's age]
Sub y = 25 into x + y = 70
x + 25 = 70
x = 45 [Mother's age]
Check my thinking
Equation 1 : x - 5 = 2*(y - 5)
Equation 2: x + 6 + y + 6 = 82
x - 5 = 2y -10 (1)
x + y + 12 = 82 (2)
x -2y = -5
x + y = 70 [Eliminate x]
-3y = -75
y = 25 [Son's age]
Sub y = 25 into x + y = 70
x + 25 = 70
x = 45 [Mother's age]
Check my thinking
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