Asked by jamie edwards
Given an equation of a line, find equations for lines parallel or perpendicular to it going through specified points. Find the appropriate equations and points from the table below. Simplify your equations into slope-intercept form.
The equation is y=3x+3 (-1,_-1)
The equation is y=3x+3 (-1,_-1)
Answers
Answered by
Alexis
Slope intercept form: y=mx+b. Having the equation y=3x+3 its already in slope intercept form.
Answered by
Steve
for the parallel line, you have a slope and a point, so use the point-slope form to get
y+1 = 3(x+1)
The perp. line has slope -1/3, so it is
y+1 = -1/3 (x+1)
Now massage those into slope-intercept form.
y+1 = 3(x+1)
The perp. line has slope -1/3, so it is
y+1 = -1/3 (x+1)
Now massage those into slope-intercept form.
Answered by
Daddy
what is the equation of the through (-6, -5) and (-4, -4) in slope inercept form
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