Asked by krista

The equation of line AB is (y-3) = 5 (x - 4). What is the slope of a line perpendicular to line AB?
Answered by Damon
y - 3 = 5 x -20
y = 5 x - 17
slope m = 5
slope of perpendicular = -1/m = -1/5
Answered by Iqbal
y - 3 = 5 x -20
y = 5 x - 17
slope m = 5
slope of perpendicular = -1/m = -1/5
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