y - 3 = 5 x -20
y = 5 x - 17
slope m = 5
slope of perpendicular = -1/m = -1/5
The equation of line AB is (y-3) = 5 (x - 4). What is the slope of a line perpendicular to line AB?
2 answers
y - 3 = 5 x -20
y = 5 x - 17
slope m = 5
slope of perpendicular = -1/m = -1/5
y = 5 x - 17
slope m = 5
slope of perpendicular = -1/m = -1/5