Question

What is the equation of a line that is perpendicular to the line x-4y=8 that passes through the point (-3,5)?




What is the equation of a line that is perpendicular to the line x-4y=8 that passes through the point (-3,5)?


y=¼x+ 23⁄4


y=-¼x+17⁄4


y=4x+17


y=-4x-7

Answer 1

Which of the following is NOT part of a place setting?


Which of the following is NOT part of a place setting?


cuchara


pollo


tenedor


cuchillo

Answer 2

To find the equation of a line that is perpendicular to the line x-4y=8, we need to determine the slope of the given line.

To do this, we can rearrange the equation into slope-intercept form y = mx + b, where m represents the slope:
x - 4y = 8
-4y = -x + 8
y = 1/4x - 2

The slope of the given line is 1/4.

Perpendicular lines have slopes that are negative reciprocals of each other. Since the slope of the given line is 1/4, the slope of the perpendicular line will be -4.

Now, we have the slope (-4) and the point (-3, 5). We can use the point-slope form of a line to find the equation:
y - y1 = m(x - x1)
y - 5 = -4(x - (-3))
y - 5 = -4(x + 3)
y - 5 = -4x - 12
y = -4x - 12 + 5
y = -4x - 7

Therefore, the equation of a line that is perpendicular to the line x-4y=8 and passes through the point (-3,5) is y = -4x - 7.