Question
I have been told that to prepare 1L of 70% H2SO4 from concentrated sulphuric acid (96% with density 1.84g/ml), I should use the following equation to find out the volume of conc. acid needed (Vml).
V x 1.84 x 0.96={(1000-V)+ 1.84V}0.7
i.e. V= 594ml of conc H2SO4.
Use 594ml of conc H2SO4 and top up to 1L volumetric flask with water.
Can you please explain this equation to me? Many thanks for your help.
V x 1.84 x 0.96={(1000-V)+ 1.84V}0.7
i.e. V= 594ml of conc H2SO4.
Use 594ml of conc H2SO4 and top up to 1L volumetric flask with water.
Can you please explain this equation to me? Many thanks for your help.
Answers
Use the equation:
V1C1 = V2C2
(V1)((0.96) = (1000mls)(0.70)
Solve for V1
V1C1 = V2C2
(V1)((0.96) = (1000mls)(0.70)
Solve for V1
After looking at your question more carefully, I changed my mind. The equation, V1C1 = V2C2, works only if <b>the concentrations are ratios of amount of solute over volume of solution</b>. The formula you are using is new to me and since you have made substitutions into it I am not sure what its correct form is.
Your question is not clear either. Are you asking about how to use that formula, or how to derive it?
Your question is not clear either. Are you asking about how to use that formula, or how to derive it?
I would like to know how to derive it, please?
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