Asked by Tresford
Describe how you would prepare 0.05 mol.dm-3 sodium carbonate in a total volume 250 mls.
Answers
Answered by
DrBob222
For a 0.05 M (that's 0.05 mol/dm^3) Na2CO3 in 250 mL, how many mols Na2CO3 is that? That's mols = M x L = 0.05 M x 0.250 L = 0.0125 mols.
Then mols = grams/molar mass. You know mols and molar mass, solve for grams. To prepare such a solution, you add the grams Na2CO3 to an empty (and dry) 250 mL volumetric flask. Add about 100 mL distilled (or deionized) water, swirl until Na2CO3 is dissolved, then add water to the mark on the volumetric flask. Stopper, mix thoroughly, label. Done.
Then mols = grams/molar mass. You know mols and molar mass, solve for grams. To prepare such a solution, you add the grams Na2CO3 to an empty (and dry) 250 mL volumetric flask. Add about 100 mL distilled (or deionized) water, swirl until Na2CO3 is dissolved, then add water to the mark on the volumetric flask. Stopper, mix thoroughly, label. Done.
Answered by
Benson
Good and helpful
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.