Asked by Janice
The following information is available.
H0 : μ ≥ 220
H1 : μ < 220
A sample of 64 observations is selected from a normal population. The sample mean is 215, and the population standard deviation is 15. Conduct the following test of hypothesis using the .025 significance level.
a.
Is this a one- or two-tailed test?
One-tailed test
b.
What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)
H0 when z < -2.00
c.
What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)
Value of the test statistic= ? I cannot not calculate this one I think it is 2.667, but it is wrong
d.
What is your decision regarding H0?
Reject
e.
What is the p-value? (Round your answer to 4 decimal places.)
p-value=.0038
H0 : μ ≥ 220
H1 : μ < 220
A sample of 64 observations is selected from a normal population. The sample mean is 215, and the population standard deviation is 15. Conduct the following test of hypothesis using the .025 significance level.
a.
Is this a one- or two-tailed test?
One-tailed test
b.
What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)
H0 when z < -2.00
c.
What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)
Value of the test statistic= ? I cannot not calculate this one I think it is 2.667, but it is wrong
d.
What is your decision regarding H0?
Reject
e.
What is the p-value? (Round your answer to 4 decimal places.)
p-value=.0038
Answers
Answered by
PsyDAG
Accept H1 when z < 1.96
Z = (score-mean)/SEm
SEm = SD/√n
Z = (215-220)/(15/8) = -5/1.875 = -2.667
Agree with e.
Z = (score-mean)/SEm
SEm = SD/√n
Z = (215-220)/(15/8) = -5/1.875 = -2.667
Agree with e.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.