Asked by Greg
write the equation in vertex form, of a parabola with vertex (5, -1) and that passes through the point (6, 8)
Answers
Answered by
Henry
Y = a(x-h)^2 + k.
8 = a(6-5)^2 - 1,
8 = a - 1, a = 9.
Y = 9(x-5)^2 - 1.
8 = a(6-5)^2 - 1,
8 = a - 1, a = 9.
Y = 9(x-5)^2 - 1.
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