Asked by Chase
Write this equation in vertex and standard form. y=-11x^2+176x-429
Answers
Answered by
oobleck
y = -11x^2 + 176x - 429
it is already in standard form!
y = -11(x^2 - 16x) - 429
y = -11(x^2-16x+64) - 429 - 11*64
y = -11(x-8)^2 - 1133
it is already in standard form!
y = -11(x^2 - 16x) - 429
y = -11(x^2-16x+64) - 429 - 11*64
y = -11(x-8)^2 - 1133
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