Asked by Bob
If cos of theta= -7/12 and theta is in quadrant 2 then find
a. tan(theta) cot (theta)=
b. csc(theta) tan(theta)=
c. sin^2(theta)+ cos^2(theta)=
a. tan(theta) cot (theta)=
b. csc(theta) tan(theta)=
c. sin^2(theta)+ cos^2(theta)=
Answers
Answered by
Steve
cosθ = x/r, so
x = -7
r = 12
y = √95
Now, recall that
sinθ = y/r
tanθ = y/x
and let 'er rip.
(a) and (c) should require no calculation at all...
x = -7
r = 12
y = √95
Now, recall that
sinθ = y/r
tanθ = y/x
and let 'er rip.
(a) and (c) should require no calculation at all...
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