Asked by Sarah

I am completely lost with this question. If 50 ml of 0.5M HCl is added to 800 ml of pure water, what will be the approximate pH of the resulting solution?

Answers

Answered by DrBob222
First you must assume that the volumes are additive; i.e., the total volume will be 850
(HCl) = 0.5M x (50/850) = ?
Then pH = -log(HCl) = ?
Answered by Sarah
Thank you so much!
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