Asked by Marie
I am completely lost trying to solve this problem. I could really use some help and explanation.
x/x+1 + 5/x = 1/x^2+x
also how do you write
(x-5)(x-5) would it be x^2-5
x/x+1 + 5/x = 1/x^2+x
also how do you write
(x-5)(x-5) would it be x^2-5
Answers
Answered by
Helper
You need parenthesis.
I'll assume your problem is,
x/(x+1) + 5/x = 1/(x^2 + x)
x/(x+1) + 5/x = 1/(x(x + 1))
Multiply both sides by x(x + 1)
x^2 + 5(x + 1) = 1
x^2 + 5x + 5 = 1
x^2 + 5x + 4 = 0
(x + 1)(x + 4) = 0
x = -1 or x = -4
Make sure you check both answers in the original equation. I have NOT checked.
I'll assume your problem is,
x/(x+1) + 5/x = 1/(x^2 + x)
x/(x+1) + 5/x = 1/(x(x + 1))
Multiply both sides by x(x + 1)
x^2 + 5(x + 1) = 1
x^2 + 5x + 5 = 1
x^2 + 5x + 4 = 0
(x + 1)(x + 4) = 0
x = -1 or x = -4
Make sure you check both answers in the original equation. I have NOT checked.
Answered by
Paige
I have been trying to figure this problem out and I am completely lost.
Could someone help guide me through it?
(3x^4-0x^3-8x^2 -3x-3) / (x^2-3)
Could someone help guide me through it?
(3x^4-0x^3-8x^2 -3x-3) / (x^2-3)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.