Question
I am completely lost trying to solve this problem. I could really use some help and explanation.
x/x+1 + 5/x = 1/x^2+x
also how do you write
(x-5)(x-5) would it be x^2-5
x/x+1 + 5/x = 1/x^2+x
also how do you write
(x-5)(x-5) would it be x^2-5
Answers
You need parenthesis.
I'll assume your problem is,
x/(x+1) + 5/x = 1/(x^2 + x)
x/(x+1) + 5/x = 1/(x(x + 1))
Multiply both sides by x(x + 1)
x^2 + 5(x + 1) = 1
x^2 + 5x + 5 = 1
x^2 + 5x + 4 = 0
(x + 1)(x + 4) = 0
x = -1 or x = -4
Make sure you check both answers in the original equation. I have NOT checked.
I'll assume your problem is,
x/(x+1) + 5/x = 1/(x^2 + x)
x/(x+1) + 5/x = 1/(x(x + 1))
Multiply both sides by x(x + 1)
x^2 + 5(x + 1) = 1
x^2 + 5x + 5 = 1
x^2 + 5x + 4 = 0
(x + 1)(x + 4) = 0
x = -1 or x = -4
Make sure you check both answers in the original equation. I have NOT checked.
I have been trying to figure this problem out and I am completely lost.
Could someone help guide me through it?
(3x^4-0x^3-8x^2 -3x-3) / (x^2-3)
Could someone help guide me through it?
(3x^4-0x^3-8x^2 -3x-3) / (x^2-3)
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