Asked by Ashley
Evaluate ∫-3,3 x^z+2x+1dx using the definition of integration
Answers
Answered by
Steve
If you mean
∫[-3,3] x^2+2x+1 dx
then the integral is
x^3/3 + x^2 + x [-3,3]
= (9+9+3)-(-9+9-3)
= 24
or,
∫(x+1)^2 dx
= 1/3 (x+1)^3 [-3,3]
= 1/3 (4^3+2^3)
= 24
∫[-3,3] x^2+2x+1 dx
then the integral is
x^3/3 + x^2 + x [-3,3]
= (9+9+3)-(-9+9-3)
= 24
or,
∫(x+1)^2 dx
= 1/3 (x+1)^3 [-3,3]
= 1/3 (4^3+2^3)
= 24
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