Asked by Anonymous
The following information is given for ether, C2H5OC2H5, at 1atm:
boiling point = 34.6 °C Hvap(34.6 °C) = 26.5 kJ/mol
specific heat liquid = 2.32 J/g°C
At a pressure of 1 atm,__kJ of heat are needed to vaporize a 25.1 g sample of liquid ether at its normal boiling point of 34.6 °C.
boiling point = 34.6 °C Hvap(34.6 °C) = 26.5 kJ/mol
specific heat liquid = 2.32 J/g°C
At a pressure of 1 atm,__kJ of heat are needed to vaporize a 25.1 g sample of liquid ether at its normal boiling point of 34.6 °C.
Answers
Answered by
DrBob222
q = mols ether x Hvap.
mols = grams/molar mass = ?
You know Hvap and can solve for mols. Substitute and solve for q.
mols = grams/molar mass = ?
You know Hvap and can solve for mols. Substitute and solve for q.
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