Asked by Monica
A skateboarded decides to jump off a ramp. The path of the jump from the ramp can be approximated by:
h = -3t^2 + 6t + 1
Where h is the height above the ground in meters, s is the horizontal displacement and t is the time after leaving the ramp in seconds. Find the maximum height reached by the skateboarder
h = -3t^2 + 6t + 1
Where h is the height above the ground in meters, s is the horizontal displacement and t is the time after leaving the ramp in seconds. Find the maximum height reached by the skateboarder
Answers
Answered by
Reiny
Where is "s" in your question ?
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