If you were to jump from an airplane at an altitude of 15000 ft. and fall toward the Earth at 100 mph how long would it take to reach the surface?
2 answers
time= distance/velocity
Your velocity would not remain constant.
Your velocity would increase by 32.2 ft./sec./sec. = 32.2 ft./sec/^2
The time to reach the ground (ignoring the earth;s curvature) derives from h = Vot + gt^2 where Vo = the initial vertical velocity = 0, g = the acceleration due to gravity, 32.2 ft./sec.^2, and t = the time to impact.
Therefore, 15,555(5280) = 32,2t^2 making t = sqrt(15000(5280)/32.2)
This, of course, ignores atmosheric drag and terminal velocity.
Your velocity would increase by 32.2 ft./sec./sec. = 32.2 ft./sec/^2
The time to reach the ground (ignoring the earth;s curvature) derives from h = Vot + gt^2 where Vo = the initial vertical velocity = 0, g = the acceleration due to gravity, 32.2 ft./sec.^2, and t = the time to impact.
Therefore, 15,555(5280) = 32,2t^2 making t = sqrt(15000(5280)/32.2)
This, of course, ignores atmosheric drag and terminal velocity.
3 answers