Question
If you were to jump from an airplane at an altitude of 15000 ft. and fall toward the Earth at 100 mph how long would it take to reach the surface?
Answers
bobpursley
time= distance/velocity
tchrwill
Your velocity would not remain constant.
Your velocity would increase by 32.2 ft./sec./sec. = 32.2 ft./sec/^2
The time to reach the ground (ignoring the earth;s curvature) derives from h = Vot + gt^2 where Vo = the initial vertical velocity = 0, g = the acceleration due to gravity, 32.2 ft./sec.^2, and t = the time to impact.
Therefore, 15,555(5280) = 32,2t^2 making t = sqrt(15000(5280)/32.2)
This, of course, ignores atmosheric drag and terminal velocity.
Your velocity would increase by 32.2 ft./sec./sec. = 32.2 ft./sec/^2
The time to reach the ground (ignoring the earth;s curvature) derives from h = Vot + gt^2 where Vo = the initial vertical velocity = 0, g = the acceleration due to gravity, 32.2 ft./sec.^2, and t = the time to impact.
Therefore, 15,555(5280) = 32,2t^2 making t = sqrt(15000(5280)/32.2)
This, of course, ignores atmosheric drag and terminal velocity.