Asked by Micheal
An 80 kg person decides to jump off the back end of a 30 kg canoe. His friend measures the speed of the canoe after he jumps to be 0.8 m/s. The canoe was initially at rest. What rule would I use to find the speed of the person who jumped?
Answers
Answered by
Steve
initially there was 0 momentum. That momentum is conserved. So, assigning the canoe's direction as negative,
30*(-.8) + 80*v = 0
80v = 24
v = +.3m/s
30*(-.8) + 80*v = 0
80v = 24
v = +.3m/s
Answered by
bobpursley
conservation of momentum
initial mometum= final momentum
(80+30)Vc=30*.8-80*V
but Vc=0, the canoe was not moving initially. Solve for V
initial mometum= final momentum
(80+30)Vc=30*.8-80*V
but Vc=0, the canoe was not moving initially. Solve for V
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.