Question

A man with a mass of 52 kg stands up in a 66-kg canoe of length 4.0 m floating on water. He walks from a point 0.75 m from the back of the canoe to a point 0.75 m from the front of the canoe. Assume negligible friction between the canoe and the water. How far does the canoe move? (Assume the canoe has a uniform density such that its center of mass location is at the center of the canoe.)

Answer 1

CM does not move.

52*(4-1.5)+66*X=0
solve for X

Answer 2

this didn't work