Question

What mass of iron can be obtained from 500.0g of Fe3O4?

I am having a hard time getting started on this question. I think I need to find the percent of iron in the compound and then multiply that by 500.0 g. But, when I tried that I got a really wonky answer.


Fe 3 55.85g/mol = 167.55/mol
O 4 16.00g/mol = 64.00g/mol
-----------
231.55g/mol

231.55g/mol = total molar mass

167.55g/mol Fe
-------------- x 100% = 72.36%
231.55g/mol

.7236% Fe x 500.0g = 361.8g

Did I get this right or do I need some major help?

Answers

Scott
looks fine

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