Asked by I.D.C.I.I.C.I.S.S.I.N.T.D.W.H.T.B.D.
A ball of iron with a mass of 252 g was heated using 2263 J of energy. The initial temperature was 547 deg * C What was the final temperature of the Iron? (The specific heat capacity for iron is 0.449 * J/(g deg * C) ,) (1 point)
24.8 ^ (- C)
O - 527 ^ (- C)
O 567 deg * C
0.04 deg * C
24.8 ^ (- C)
O - 527 ^ (- C)
O 567 deg * C
0.04 deg * C
Answers
Answered by
Damon
energy in = 2263 J = rise in temp * 0.449 J/g deg C * 252 g
so
rise in temp = 2263 / (.449 * 252) = 20 degrees C
547 + 20 = 567 degrees C
so
rise in temp = 2263 / (.449 * 252) = 20 degrees C
547 + 20 = 567 degrees C
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