Question
An iron bar of mass, 0.6 kg, slides down a frictionless incline 0.38 m high. At the bottom of the incline it collides and sticks to a magnet of mass, 0.94 kg. What is the speed of the combined masses after collision.
Answers
Damon
speed at bottom = sqrt(2 g h)
= sqrt (2 * 9.81 * .38)
= 2.73 m/s
momentum before crash = .6*2.73 = 1.64 kg m/s
same momentum after of course
new mass = .6 + .94 = 1.54 kg
so
1.64 = 1.54 v
v = 1.06 m/s
= sqrt (2 * 9.81 * .38)
= 2.73 m/s
momentum before crash = .6*2.73 = 1.64 kg m/s
same momentum after of course
new mass = .6 + .94 = 1.54 kg
so
1.64 = 1.54 v
v = 1.06 m/s