Asked by Pat


Two hikers are 22

miles apart and walking toward each other. They meet in 5

hours. Find the rate of each hiker if one hiker walks 2.2

mph faster than the other.

Answers

Answered by Henry
1st hiker walks X mi/h.
2nd hiker walks (x+2.2) mi/h.

d1 + d2 = 22 miles.
sx + 5(x+2.2) = 22. X = ?.


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