Asked by Pat
Two hikers are 22
miles apart and walking toward each other. They meet in 5
hours. Find the rate of each hiker if one hiker walks 2.2
mph faster than the other.
Answers
Answered by
Henry
1st hiker walks X mi/h.
2nd hiker walks (x+2.2) mi/h.
d1 + d2 = 22 miles.
sx + 5(x+2.2) = 22. X = ?.
2nd hiker walks (x+2.2) mi/h.
d1 + d2 = 22 miles.
sx + 5(x+2.2) = 22. X = ?.
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