Asked by ashwani
.Two hikers begin at the same location and walk in perpendicular directions. Hiker A travels due north at a rate of 3 miles per hour; Hiker B travels due east at a rate of 5 miles per hour. At what rate is the distance between the two hikers changing 4 hours into the hike?
Answers
Answered by
Reiny
let the time passed be t hours
Simple right-angled triangles
let the distance between them be D
D^2 = (3t)^2 + (5t)^2
D^2 = 34t^2
D = √34 t
dD/dt = √34
So the distance between them is changing at a constant rate of √34 mph, independent of the time
Simple right-angled triangles
let the distance between them be D
D^2 = (3t)^2 + (5t)^2
D^2 = 34t^2
D = √34 t
dD/dt = √34
So the distance between them is changing at a constant rate of √34 mph, independent of the time
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