Question

Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.What is the mole fraction of N2 in the mixture?

Answer 1

P V = n R T

V, T and R are the same for each
so
n, the number of mols is proportional to P

total pressure = 3.5 + 2.8 + .25 + .15 = 6.7
so for example mol fraction of N2 = 3.5/6.7 = .522

Answer 2

thank you so much you are a great help have a nice day. you are an amazing and smart person!

Answer 3

this doesnt help my equation lol thanks alot tho

Answer 4

Where, was, why the answer?

Answer 5

0.52

Answer 6

6.7 atm is the answer

Answer 7

What is the total pressure inside the cylinder?
6.7 atm
What is the mole fraction of N2 in the mixture?
0.52 atm

Answer 8

for the next half:
What is the mole fraction of O2 in the mixture? .42
What is the mole fraction of Ar in the mixture? .037