Asked by Jimbo
A stone is dropped from a hot air balloon that is rising at a constant speed of 2.2 m/s. If the stone takes 4.8 seconds to reach the ground then …
a) What was the height of the balloon at the moment the stone was released?
b) What is the height of the balloon at the time the stone hit the ground?
a) What was the height of the balloon at the moment the stone was released?
b) What is the height of the balloon at the time the stone hit the ground?
Answers
Answered by
bobpursley
hf=0=hi+vi*t-1/2 g t^2
you are given vi, and time t.
solve for initial height hi
hf=hi+2.2*4.8 use hi form above, solve for hf the final height of the balloon at time of stone crash.
you are given vi, and time t.
solve for initial height hi
hf=hi+2.2*4.8 use hi form above, solve for hf the final height of the balloon at time of stone crash.
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