Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
What are the molality and mole fraction of solute in a 25.5 percent by mass aqueous solution of formic acid (HCOOH)?Asked by Daryll
What are the molality and mole fraction of solute in a 30.1 percent by mass aqueous solution of formic acid (HCOOH)
Answers
Answered by
DrBob222
In a 100 g sample, you will have 30.1 g HCOOH and 69.9 g H2O.
mols HCOOH = 30.1/molar mass = ?
Then m = mols HCOOH/0.1 kg solvent = ?
XHCOOH = mols HCOOH/total mols.
You have mols HCOOH. mols H2O \ grams H2O/molar mass = ?
mols HCOOH = 30.1/molar mass = ?
Then m = mols HCOOH/0.1 kg solvent = ?
XHCOOH = mols HCOOH/total mols.
You have mols HCOOH. mols H2O \ grams H2O/molar mass = ?