Asked by c
Find the molality, mole fraction, and percent by mass of a solution prepared with 500 grams of C12h22O11 in 2000 grams of H20
Answers
Answered by
DrBob222
mols C12H22O11 = grams/molar mass
m = mols/kg
You have mols C12H22O11. Convert 2000 g H2O to mols and find total mols.
Then XC12H22O11 = mols C12H22O11/total mols.
%w/w = [(grams C12H11O11/(2000g H2O + grams C12H22O11)]*(100 = ?
m = mols/kg
You have mols C12H22O11. Convert 2000 g H2O to mols and find total mols.
Then XC12H22O11 = mols C12H22O11/total mols.
%w/w = [(grams C12H11O11/(2000g H2O + grams C12H22O11)]*(100 = ?