Asked by Daryll

What are the molality and mole fraction of solute in a 30.1 percent by mass aqueous solution of formic acid (HCOOH)

can you please explain it better? I still don't quite understand
Answered by bobpursley
assume 1000g of solution
so 301 grams of it is formic acid, and 699 grams of water.

moles of water=699/18= ...
moles of formic acid=301/molmass=..

mole fraction=molesacid/totalmoles
molality= molesacid/.699

Answered by DrBob222
Daryll, "Explain it further" doesn't help much. Did you try following each of the formulas I gave. Exactly what do you not understand. Do it step by step, show your work, and explain each part you don't understand.
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