Asked by Mike
Mary is riding a merry-go-round, whose radius is 25 feet and which is turning 36 degrees per second. Seeing a friend in the crowd, she steps off the the outer edge of the merry-go-round and suddenly finds it necessary to run? At how many miles per hour does she have to run?
Answers
Answered by
Steve
since 1 revolution is 360 degrees,
(25 * 2π ft/rev) * (2π/10 rev/s) * 3600s/hr * 1mi/5280 ft = 10.71 mi/hr
(25 * 2π ft/rev) * (2π/10 rev/s) * 3600s/hr * 1mi/5280 ft = 10.71 mi/hr
Answered by
Reiny
At the moment she steps off, her linear velocity equals the rate the arc length is increasing.
circumference = 2π(25) = 50π ft
36° = 36/360 = 1/10 of a rotation
so the linear velocity of any point is 5π ft/second
5π ft/1 second
= (5π/5280) / (1/3600) miles/hour
= (5π/(5280)(3600) mph
= appr 10.7 mph
circumference = 2π(25) = 50π ft
36° = 36/360 = 1/10 of a rotation
so the linear velocity of any point is 5π ft/second
5π ft/1 second
= (5π/5280) / (1/3600) miles/hour
= (5π/(5280)(3600) mph
= appr 10.7 mph
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