Asked by Anonymous
                A ball is thrown vertically downward with a velocity of 12m/s How far has the ball fallen 1 s later?. 2s later?
            
            
        Answers
                    Answered by
            Anonymous
            
    h=vₒt+gt²/2,
v=12
t=1
g=9.9
    
v=12
t=1
g=9.9
                    Answered by
            bobpursley
            
    d=vo*time+1/2 g t^2
vo=-12m/s
g=-9.8m/s^2
find d (1sec)
I am not certain if you want the total distance, or distance in the ,2 sec. If that,
d=d(1.2)-d(1)
    
vo=-12m/s
g=-9.8m/s^2
find d (1sec)
I am not certain if you want the total distance, or distance in the ,2 sec. If that,
d=d(1.2)-d(1)
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