Asked by Jay
A lemming runs horizontally off the side of a 27.8 m cliff at 1.12 m/s. How long will it take for the lemming to hit the water? How far will it travel in the horizontal direction?
Answers
Answered by
Damon
u = 1.12 forever
Vi =initial vertical velocity = 0
v = Vi - 9.81 t
h = Hi + Vi t - 4.9 t^2
h = 27.8 - 4.9 t^2
0 = 27.8 - 4.9 t^2
so
t = sqrt (27.8/4.9)
use that t to get horizontal range
x = 1.12 t
Vi =initial vertical velocity = 0
v = Vi - 9.81 t
h = Hi + Vi t - 4.9 t^2
h = 27.8 - 4.9 t^2
0 = 27.8 - 4.9 t^2
so
t = sqrt (27.8/4.9)
use that t to get horizontal range
x = 1.12 t
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