a. (0.5 m/s)*(fall time)
b. sqrt[(g*(fall time))^2 +0.5^2]
c. (M)[gH + (0.5)^2/2]
where the "fall time" is sqrt(2H/g)
H = 4.9 m
g = 9.8 m/s^2
M = 0.4 kg
Crank it out.
A 400g lemming waddles horizontally off a small 4.9m high cliff with a horizontal
velocity of 0.5m/s.
a. How far from the base of the cliff will the lemming land?
b. What will be the lemmings speed just before landing?
c. What is the lemmings kinetic energy just before landing?
2 answers
A ball rolls horizontally of an 85 m cliff with a velocity of 11 m/s. How far from the base of the cliff will it land?
1 answer