Question

the sum of the digits of a three digit number is 20. the middle digit is equal to one fourth the sum of the other two. if the order of the digits be reversed the number increases the original by 198 find the original number

Answer 1

let the digit be abc

a+b+c=20

b=1/4(a+c)

100a+10b+c=100b+10c+b+198

now solve for abc and good luck

Answer 2

I coudnt solve.

Answer 3

I coudnt solve. Couldn't solve for abc

Answer 4

I couldn't solve.