the sum of the digits of a three digit number is 14.
the tens digits exceeds twice the hundred digit by one.
If 3 were added to the number,
the units and hundreds digit would be the same.
find the number.
solve
H = hundred digit
t in ten digit
u in unit digit
sum of the digits of 3 digit number is 14: H+t+u=14
ten digits exceeds twice the hundred digit by one: t-2h+1
if 3 were added to the number, the units and hundred digit would be the same: u-2h+1+3 = h-2h+1+3
therefore, u-2h+4+h-4=0
u-h=0
i don't know what is next step, but the answer given for this problem is 491. i don't know how to get this answer 491.
could some one please help? Thank you.
1 answer
please help i get stuck on this problem
1 answer