Asked by Sara
what are the coordinates of the vertex of f(x)=-x^2+6x-9
(0,-9)
(3,-9)
(3,0)
(6,0)
How do I figure this out?
(0,-9)
(3,-9)
(3,0)
(6,0)
How do I figure this out?
Answers
Answered by
Scott
the vertex is on the axis of symmetry
x = -b / (2 a) = -6 / (2 * -1) = 3
plug 3 into the function to find the y-coordinate
x = -b / (2 a) = -6 / (2 * -1) = 3
plug 3 into the function to find the y-coordinate
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