Starting from rest an airplane moves with a constant acceleration of 2m/s for 30 seconds before it takes off

A. d = Vo*t + 0.5a*t^2.

d = 0 + 1*30^2 =

B. V = a*t.

1.00m

To find the answers to these questions, we can use the equations of motion.

A. The distance traveled, also known as displacement, can be found using the equation:
displacement = initial velocity * time + (1/2) * acceleration * time^2

In this case, the initial velocity is zero since the airplane starts from rest. The acceleration is given as 2 m/s^2, and the time is 30 seconds. Plugging these values into the equation:

displacement = 0 * 30 + (1/2) * 2 * (30^2)
= 0 + 1 * (900)
= 900 meters

Therefore, the airplane travels 900 meters down the runway before it takes off.

B. The final velocity can be found using the equation:
final velocity = initial velocity + acceleration * time

Again, the initial velocity is zero. Plugging in the given values:

final velocity = 0 + 2 * 30
= 60 m/s

Therefore, the final velocity of the airplane is 60 m/s.