Question

Starting from rest at 10m to the left of the origin (the starting line of a race), a go-kart undergoes constant acceleration of 2.46 m/s2. Make a table calculating the karts position and velocity at 10 second intervals from t=0 to 60 seconds. I have created the table but I need help with the equations to use to find the position and the velocity?

Answer 1

v = a t = 2.46 t
x = -10 + (1.23) t^2