Question

a body moves for a total of 9 seconds starting from rest with uniform acceleration and then with uniform retardation which is twice of value of acceleration to stop .what is the duration of uniform acceleration

Answer 1

v=u+at

Answer 2

Distance covered in 4 secods after tha 5th seconds= S9- s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n-1)

Answer 3

Distance covered in 4 secods after tha 5th seconds= S9- s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n-1) The modern sr. sec. Bagpur palwal phone no. 8059892363

Answer 4

Use v=u+at and form two equations one for acc. And one for retard. Then on solving u will get d ans. I hope dat helps.. 😀 ☺

Answer 5

5s

Answer 6

Yesss